目錄

• 需求分析
• 解決步驟
• 最終結(jié)果
• 技術(shù)總結(jié)

需求分析

根據(jù)原始數(shù)據(jù)，計算出累計和、回撤、連續(xù)正確、連續(xù)錯誤、連續(xù)正確值與連續(xù)錯誤值6項數(shù)據(jù)，其中原始數(shù)據(jù)大于等于0認定為正確，原始數(shù)據(jù)小于0為錯誤。明白了要求，那我們就開始擼代碼吧~

解決步驟

import pandas as pd#創(chuàng)建一個計算數(shù)據(jù)得函數(shù)def calculate(df):  pass#讀取原始數(shù)據(jù)，將索引列去除df = pd.read_excel('需求0621.xlsx',index_col=0)#調(diào)用計算數(shù)據(jù)得函數(shù)calculate(df)

先把整體思路寫好，再去想辦法計算每項數(shù)據(jù)

#計算累計和    lst1 = []    sum = 0    for i in range(df.shape[0]):        if i == 0:            lst1.append(df['N'][i])            sum += df['N'][i]        else:            sum += df['N'][i]            lst1.append(sum)    df['累計和'] = lst1

#計算回撤    lst2 = []    max = 0    for i in range(df.shape[0]):        if i == 0:            lst2.append(0)        elif df['累計和'][i] > max:            max = df['累計和'][i]            lst2.append(0)        elif df['累計和'][i] < max:            lst2.append(df['累計和'][i]-max)        elif df['累計和'][i] == max:            lst2.append(0)    df['回撤'] = lst2

#計算連續(xù)正確得個數(shù)    lst3 = []    correct = 0    for i in range(df.shape[0]):        if df['N'][i] >= 0:            correct += 1            lst3.append(correct)        else:            lst3.append(0)            correct = 0    df['連續(xù)正確'] = lst3

#計算連續(xù)錯誤得個數(shù)    lst4 = []    mistake = 0    for i in range(df.shape[0]):        if df['N'][i] < 0:            mistake += 1            lst4.append(mistake)        else:            lst4.append(0)            mistake = 0    df['連續(xù)錯誤'] = lst4

#計算連續(xù)正確值    lst5 = []    for i in range(df.shape[0]):        lst5.append('')    right = 0    for i in range(df.shape[0]):        if df['連續(xù)正確'][i] != 0:            right += df['N'][i]        elif df['連續(xù)正確'][i] == 0 and right != 0:            lst5[i-1] = right            right = 0    df['連續(xù)正確值'] = lst5

#計算連續(xù)錯誤值    lst6 = []    for i in range(df.shape[0]):        lst6.append('')    wrong = 0    for i in range(df.shape[0]):        if df['連續(xù)錯誤'][i] != 0:            wrong += df['N'][i]        elif df['連續(xù)錯誤'][i] == 0 and wrong != 0:            lst6[i-1] = wrong            wrong = 0    df['連續(xù)錯誤值'] = lst6

最后將dataframe保存到excel

    df.to_excel('完成計算.xlsx')    print('保持成功')

最終結(jié)果

技術(shù)總結(jié)

雖然已經(jīng)完成了要求計算出了所有得數(shù)據(jù)，但在寫代碼過程中計算得步驟都是基于python基礎(chǔ)語法實現(xiàn)得，對于pandas得使用還要只有通過大量得練習才能夠熟練得掌握

到此這篇關(guān)于利用Python實現(xiàn)簡單得Excel統(tǒng)計函數(shù)得內(nèi)容就介紹到這了,更多相關(guān)Python實現(xiàn)Excel統(tǒng)計函數(shù)內(nèi)容請搜索之家以前得內(nèi)容或繼續(xù)瀏覽下面得相關(guān)內(nèi)容希望大家以后多多支持之家！